1. **Find the distance between parks C and D on the map.** Given: Each unit on the grid equals 25 miles. Coordinates: C(-2, 2), D(5, -1). 2. **Use the distance formula:** $$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$ 3. **Calculate the differences:** $$x_2 - x_1 = 5 - (-2) = 7$$ $$y_2 - y_1 = -1 - 2 = -3$$ 4. **Calculate the distance in grid units:** $$d = \sqrt{7^2 + (-3)^2} = \sqrt{49 + 9} = \sqrt{58}$$ 5. **Convert grid units to miles:** Each unit = 25 miles, so $$d_{miles} = 25 \times \sqrt{58}$$ 6. **Calculate the numeric value:** $$d_{miles} \approx 25 \times 7.6158 = 190.4$$ 7. **Round to the nearest mile:** $$\boxed{190 \text{ miles}}$$ --- 1. **Find the perimeter of triangle ABC.** Coordinates: A(1, 2), B(7, 9), C(7, 2). 2. **Calculate each side length using the distance formula:** - Side AB: $$AB = \sqrt{(7-1)^2 + (9-2)^2} = \sqrt{6^2 + 7^2} = \sqrt{36 + 49} = \sqrt{85}$$ - Side BC: $$BC = \sqrt{(7-7)^2 + (9-2)^2} = \sqrt{0 + 7^2} = 7$$ - Side AC: $$AC = \sqrt{(7-1)^2 + (2-2)^2} = \sqrt{6^2 + 0} = 6$$ 3. **Sum the side lengths:** $$P = AB + BC + AC = \sqrt{85} + 7 + 6$$ 4. **Calculate numeric values:** $$\sqrt{85} \approx 9.22$$ $$P \approx 9.22 + 7 + 6 = 22.22$$ 5. **Round to the nearest tenth:** $$\boxed{22.2}$$