Subjects geometry

Distance Between Points Ba676B

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1. **State the problem:** We need to find the distance between each pair of points given: (-4,-2), (-2,0), (0,2), (2,4), and (3,5). 2. **Formula used:** The distance $d$ between two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the distance formula: $$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$ 3. **Calculate distances:** - Between $(-4,-2)$ and $(-2,0)$: $$d = \sqrt{(-2 - (-4))^2 + (0 - (-2))^2} = \sqrt{(2)^2 + (2)^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2} \approx 2.8$$ - Between $(-2,0)$ and $(0,2)$: $$d = \sqrt{(0 - (-2))^2 + (2 - 0)^2} = \sqrt{(2)^2 + (2)^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2} \approx 2.8$$ - Between $(0,2)$ and $(2,4)$: $$d = \sqrt{(2 - 0)^2 + (4 - 2)^2} = \sqrt{(2)^2 + (2)^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2} \approx 2.8$$ - Between $(2,4)$ and $(3,5)$: $$d = \sqrt{(3 - 2)^2 + (5 - 4)^2} = \sqrt{(1)^2 + (1)^2} = \sqrt{1 + 1} = \sqrt{2} \approx 1.4$$ 4. **Summary:** The distances between each consecutive pair of points are approximately: - $(-4,-2)$ to $(-2,0)$: 2.8 - $(-2,0)$ to $(0,2)$: 2.8 - $(0,2)$ to $(2,4)$: 2.8 - $(2,4)$ to $(3,5)$: 1.4 These distances are rounded to the nearest tenth as requested.
(-4,-2)(-2,0)(0,2)(2,4)(3,5)