1. **State the problem:** We need to find the distance between each pair of points given: (-4,-2), (-2,0), (0,2), (2,4), and (3,5).
2. **Formula used:** The distance $d$ between two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the distance formula:
$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$
3. **Calculate distances:**
- Between $(-4,-2)$ and $(-2,0)$:
$$d = \sqrt{(-2 - (-4))^2 + (0 - (-2))^2} = \sqrt{(2)^2 + (2)^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2} \approx 2.8$$
- Between $(-2,0)$ and $(0,2)$:
$$d = \sqrt{(0 - (-2))^2 + (2 - 0)^2} = \sqrt{(2)^2 + (2)^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2} \approx 2.8$$
- Between $(0,2)$ and $(2,4)$:
$$d = \sqrt{(2 - 0)^2 + (4 - 2)^2} = \sqrt{(2)^2 + (2)^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2} \approx 2.8$$
- Between $(2,4)$ and $(3,5)$:
$$d = \sqrt{(3 - 2)^2 + (5 - 4)^2} = \sqrt{(1)^2 + (1)^2} = \sqrt{1 + 1} = \sqrt{2} \approx 1.4$$
4. **Summary:** The distances between each consecutive pair of points are approximately:
- $(-4,-2)$ to $(-2,0)$: 2.8
- $(-2,0)$ to $(0,2)$: 2.8
- $(0,2)$ to $(2,4)$: 2.8
- $(2,4)$ to $(3,5)$: 1.4
These distances are rounded to the nearest tenth as requested.
Distance Between Points Ba676B
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