1. **State the problem:** We have points $P(a,b)$ and midpoint $M(c,d)$ of segment $PQ$. We want to find expressions for the distances $PM$ and $PQ$.
2. **Recall the distance formula:** The distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by
$$\text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$
3. **Expression for $PM$:** Using the distance formula between $P(a,b)$ and $M(c,d)$,
$$PM = \sqrt{(a - c)^2 + (b - d)^2}$$
4. **Relationship between $P$, $Q$, and $M$:** Since $M$ is the midpoint of $PQ$, the coordinates of $M$ are
$$c = \frac{a + x}{2}, \quad d = \frac{b + y}{2}$$
where $Q$ has coordinates $(x,y)$.
5. **Express $Q$ in terms of $P$ and $M$:** Solving for $x$ and $y$,
$$x = 2c - a, \quad y = 2d - b$$
6. **Expression for $PQ$:** Using the distance formula between $P(a,b)$ and $Q(x,y)$,
$$PQ = \sqrt{(x - a)^2 + (y - b)^2} = \sqrt{(2c - a - a)^2 + (2d - b - b)^2} = \sqrt{(2c - 2a)^2 + (2d - 2b)^2}$$
7. **Simplify $PQ$:**
$$PQ = \sqrt{4(c - a)^2 + 4(d - b)^2} = \sqrt{4[(c - a)^2 + (d - b)^2]} = 2\sqrt{(c - a)^2 + (d - b)^2}$$
8. **Relate $PQ$ to $PM$:** Note that
$$PM = \sqrt{(a - c)^2 + (b - d)^2} = \sqrt{(c - a)^2 + (d - b)^2}$$
so
$$PQ = 2PM$$
**Final answers:**
$$PM = \sqrt{(a - c)^2 + (b - d)^2}$$
$$PQ = 2\sqrt{(a - c)^2 + (b - d)^2}$$
Distance Midpoint 2B5F42
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