1. **State the problem:** Sabrina travels from her house to a park 6.8 miles away. She first goes east 1.6 miles, then north to reach the park. We need to find how far north she travels.
2. **Identify the right triangle:** The path forms a right triangle where:
- The eastward leg is 1.6 miles (horizontal leg).
- The northward leg is unknown (vertical leg, call it $x$).
- The hypotenuse is 6.8 miles (direct distance from house to park).
3. **Use the Pythagorean theorem:** For a right triangle with legs $a$ and $b$ and hypotenuse $c$, the formula is:
$$a^2 + b^2 = c^2$$
Here, $a = 1.6$, $b = x$, and $c = 6.8$.
4. **Set up the equation:**
$$1.6^2 + x^2 = 6.8^2$$
5. **Calculate squares:**
$$2.56 + x^2 = 46.24$$
6. **Isolate $x^2$:**
$$x^2 = 46.24 - 2.56$$
$$x^2 = 43.68$$
7. **Find $x$ by taking the square root:**
$$x = \sqrt{43.68}$$
8. **Calculate the square root:**
$$x \approx 6.61$$
9. **Interpret the result:** Sabrina must travel approximately 6.6 miles north to reach the park.
**Final answer:** C. 6.6 miles
Distance North 7859Aa
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.