Subjects geometry

Distance Points 3E4Ae3

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1. **State the problem:** Find the distance between the points (7, 9) and (2, -3) using the right triangle formed by these points and the point (2, 9). 2. **Formula used:** The distance between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the distance formula derived from the Pythagorean theorem: $$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$ 3. **Identify the legs of the right triangle:** - Vertical leg length: $|9 - (-3)| = |9 + 3| = 12$ - Horizontal leg length: $|7 - 2| = 5$ 4. **Calculate the hypotenuse (distance):** $$d = \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169}$$ 5. **Simplify:** $$d = 13$$ 6. **Rounding:** The distance is exactly 13, so rounding to the nearest tenth remains 13.0. **Note:** The user mentioned leg 1 as 9 and leg 2 as 5, but the correct vertical leg is 12, not 9. Using the correct legs, the distance is 13.0. **Final answer:** The distance between the points (7, 9) and (2, -3) is $13.0$ units.