1. The problem asks us to find the distance between the points $(1,2)$ and $(4,6)$ using the Pythagorean theorem.
2. The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is derived from the Pythagorean theorem and is given by:
$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$
3. Substitute the given points into the formula:
$$d = \sqrt{(4 - 1)^2 + (6 - 2)^2}$$
4. Calculate the differences:
$$d = \sqrt{3^2 + 4^2}$$
5. Square the differences:
$$d = \sqrt{9 + 16}$$
6. Add the squares:
$$d = \sqrt{25}$$
7. Take the square root:
$$d = 5$$
Therefore, the distance between the points $(1,2)$ and $(4,6)$ is 5 units.
Distance Points F2967A
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