1. **State the problem:** We have a donut with an outer radius of 15 cm and a hole with a diameter of 10 cm (thus radius 5 cm). A bite with diameter 5 cm (radius 2.5 cm) was taken. We want to find what percentage of the bite was stolen. 2. **Identify the areas involved:** - Area of the whole donut (outer circle minus hole) - Area of the bite (circle with radius 2.5 cm) - Area stolen is the bite area minus the part overlapping the hole (since the hole is empty, that part is not stolen donut) 3. **Formulas:** - Area of a circle: $$A = \pi r^2$$ - Donut area: $$A_{donut} = \pi R^2 - \pi r^2 = \pi (R^2 - r^2)$$ where $R=15$ cm, $r=5$ cm - Bite area: $$A_{bite} = \pi (2.5)^2 = \pi \times 6.25$$ 4. **Calculate areas:** - Donut area: $$\pi (15^2 - 5^2) = \pi (225 - 25) = \pi \times 200$$ - Bite area: $$\pi \times 6.25$$ 5. **Calculate the bite area overlapping the hole:** The hole radius is 5 cm, bite radius 2.5 cm, and the bite is taken from the donut edge, so the bite overlaps the hole partially. Assuming the bite is fully on the donut edge, the overlapping area with the hole is the intersection of two circles with radii 5 and 2.5 cm, centers 15 cm apart (outer radius) minus 2.5 cm (bite radius) = 12.5 cm apart? Actually, the problem does not specify the bite position, so we assume the bite is fully on the donut part (no overlap with hole), so the entire bite area is stolen. 6. **Calculate percentage stolen:** Since the bite is fully on the donut, the entire bite area is stolen. 7. **Answer:** The percentage of the bite stolen is 100%.