1. **Problem statement:** Two of the exterior angles of a pentagon are $4x$ and $2x$. The remaining three exterior angles are each $3x$. Find: a. The value of $x$. b. Each exterior angle. 2. **Formula and rules:** The sum of exterior angles of any polygon is always $360^\circ$. 3. **Set up the equation:** Sum of exterior angles $= 4x + 2x + 3x + 3x + 3x = 360$ 4. **Simplify:** $$4x + 2x + 3x + 3x + 3x = 15x$$ So, $15x = 360$ 5. **Solve for $x$:** $$x = \frac{360}{15} = 24$$ 6. **Find each exterior angle:** - $4x = 4 \times 24 = 96^\circ$ - $2x = 2 \times 24 = 48^\circ$ - Each of the three $3x$ angles: $3 \times 24 = 72^\circ$ 7. **Summary:** a. $x = 24$ b. Exterior angles are $96^\circ$, $48^\circ$, and three angles of $72^\circ$ each. This completes the solution for the first question.