1. **Stating the problem:** We need to find the length of segment $AB$ in a trapezoid where $DC = 11.5$ units, and $MN = 18.7$ units, with $MN$ parallel to both $AB$ and $DC$.
2. **Understanding the trapezoid and segments:** In trapezoids, segments parallel to the bases and between them often relate by the properties of similar triangles or mid-segment theorems.
3. **Using the trapezoid mid-segment theorem:** The segment $MN$ is parallel to both bases $AB$ and $DC$. If $MN$ is the mid-segment between $AB$ and $DC$, then its length is the average of the lengths of $AB$ and $DC$:
$$MN = \frac{AB + DC}{2}$$
4. **Substitute known values:**
$$18.7 = \frac{AB + 11.5}{2}$$
5. **Solve for $AB$:**
Multiply both sides by 2:
$$2 \times 18.7 = AB + 11.5$$
$$37.4 = AB + 11.5$$
Subtract 11.5 from both sides:
$$37.4 - 11.5 = AB$$
$$\cancel{37.4} - \cancel{11.5} = AB$$
$$25.9 = AB$$
6. **Final answer:**
$$\boxed{AB = 25.9}$$ units.
Find Ab 657E51
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.