1. **State the problem:** We are given two similar triangles ABE and CDE with corresponding sides AB = 93 ft, BC = 98 ft, CE = 68.6 ft, and we need to find the length $d = ED$. 2. **Identify the similarity and corresponding sides:** Since the triangles are similar, the ratios of corresponding sides are equal. 3. **Set up the proportion:** The sides correspond as follows: $\frac{AB}{BC} = \frac{BE}{CE} = \frac{AE}{DE}$. 4. **Use the known sides to find $d$:** We know $AB = 93$, $BC = 98$, $CE = 68.6$, and $ED = d$. The corresponding sides $AE$ and $DE$ correspond to $BE$ and $CE$ respectively, so we use the ratio: $$\frac{BC}{CE} = \frac{AB}{ED}$$ which rearranges to: $$d = ED = \frac{CE \times AB}{BC}$$ 5. **Calculate $d$:** $$d = \frac{68.6 \times 93}{98}$$ 6. **Simplify the fraction:** $$d = \frac{\cancel{68.6} \times 93}{\cancel{98}}$$ (Here, no common factors to cancel, so proceed with multiplication and division.) 7. **Perform the multiplication and division:** $$d = \frac{6379.8}{98} = 65.1020408163$$ 8. **Final answer:** $$d = 65.1020408163 \text{ feet}$$ This is the exact value without rounding.