1. **State the problem:** We need to find the length of side $GH$ in parallelogram $EFGH$. 2. **Recall properties of parallelograms:** Opposite sides in a parallelogram are equal in length. Therefore, $GH = FE$. 3. **Given expressions:** - $GH = 2v - 42$ - $FE = v - 5$ 4. **Set the expressions equal:** Since $GH = FE$, we have: $$2v - 42 = v - 5$$ 5. **Solve for $v$:** Subtract $v$ from both sides: $$2v - 42 - \cancel{v} = \cancel{v} - 5 - v$$ $$v - 42 = -5$$ Add 42 to both sides: $$v - 42 + 42 = -5 + 42$$ $$v = 37$$ 6. **Find $GH$ by substituting $v=37$ into $GH = 2v - 42$:** $$GH = 2(37) - 42 = 74 - 42 = 32$$ **Final answer:** $$\boxed{32}$$