1. **State the problem:** We have a right triangle with angles 30°, 60°, and 90°. The side opposite the 30° angle is given as $14\sqrt{3}$ km, and we need to find the hypotenuse $q$ in simplest radical form.
2. **Recall the properties of a 30°-60°-90° triangle:**
- The side opposite 30° is half the hypotenuse.
- The side opposite 60° is $\sqrt{3}$ times the side opposite 30°.
3. **Set up the relationship:**
Let the hypotenuse be $q$. Then the side opposite 30° is $\frac{q}{2}$.
4. **Use the given side length:**
$$\frac{q}{2} = 14\sqrt{3}$$
5. **Solve for $q$:**
Multiply both sides by 2:
$$\cancel{\frac{q}{2}} \times 2 = 14\sqrt{3} \times 2$$
$$q = 28\sqrt{3}$$
6. **Final answer:**
The hypotenuse $q$ is $\boxed{28\sqrt{3}}$ kilometers.
Find Hypotenuse 15690B
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