1. **Problem Statement:** We are given a circle with points A, B, C, D on its circumference and angles marked as follows: \(\angle A = 55^\circ\) (right angle), \(\angle B = 39^\circ\), \(\angle E = 35^\circ\), and \(\angle C = x^\circ\). Segments CA and AB are equal in length.
2. **Key Information and Formula:** Since CA = AB, triangle CAB is isosceles with \(\angle C = \angle B\) or \(\angle C = x\) and \(\angle B = 39^\circ\). Also, \(\angle A = 90^\circ\) (right angle).
3. **Using Triangle Angle Sum:** The sum of angles in triangle CAB is \(180^\circ\). So,
$$x + 39 + 55 = 180$$
4. **Calculate \(x\):**
$$x = 180 - 39 - 55 = 86$$
5. **Conclusion:** The value of \(x\) is \(86^\circ\).
Find X Angle 498D3E
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