1. **Problem Statement:** We are given a right triangle with a hypotenuse of length 17 and one leg of length 13. We need to find the length of the other leg, $x$, and round it to the nearest tenth. 2. **Formula Used:** In a right triangle, the Pythagorean theorem applies: $$x^2 + 13^2 = 17^2$$ This theorem states that the sum of the squares of the legs equals the square of the hypotenuse. 3. **Calculate:** $$x^2 + 169 = 289$$ Subtract 169 from both sides: $$x^2 = 289 - 169 = 120$$ 4. **Find $x$:** $$x = \sqrt{120}$$ Simplify the square root: $$x = \sqrt{4 \times 30} = 2\sqrt{30}$$ 5. **Approximate:** $$x \approx 2 \times 5.477 = 10.954$$ 6. **Round to nearest tenth:** $$x \approx 11.0$$ **Final answer:** $x = 11.0$