1. **Stating the problem:** We are given two triangles with angles expressed in terms of $y$ and need to find the value of $y$. 2. **First triangle:** Angles are $y^\circ$, $3y^\circ$, and $80^\circ$. Since the sum of angles in a triangle is $180^\circ$, we write: $$y + 3y + 80 = 180$$ 3. **Simplify the equation:** $$4y + 80 = 180$$ 4. **Isolate $y$:** $$4y = 180 - 80$$ $$4y = 100$$ 5. **Divide both sides by 4:** $$y = \frac{100}{4}$$ $$y = 25$$ 6. **Second triangle:** Angles are $2y^\circ$ and $3y^\circ$ with $\overrightarrow{AC}$ a straight line, so these two angles are supplementary and sum to $180^\circ$: $$2y + 3y = 180$$ 7. **Simplify:** $$5y = 180$$ 8. **Solve for $y$:** $$y = \frac{180}{5}$$ $$y = 36$$ **Note:** The two triangles give different values for $y$ (25 and 36). Since the problem asks to find $y$ for the first triangle (as it appears first), the value is $\boxed{25}$.