1. **State the problem:** Calculate the surface area of a gas tank composed of a cylinder with a hemisphere on each end. 2. **Given data:** - Diameter of cylinder and hemispheres: 45 cm - Total length of tank: 79 cm 3. **Find the radius:** $$r = \frac{45}{2} = 22.5\text{ cm}$$ 4. **Find the length of the cylindrical part:** The total length includes two hemispheres, each with radius 22.5 cm, so total hemisphere length is: $$2 \times 22.5 = 45\text{ cm}$$ Subtract this from total length to get cylinder length: $$\text{cylinder length} = 79 - 45 = 34\text{ cm}$$ 5. **Surface area formulas:** - Surface area of cylinder (excluding ends): $$A_{cyl} = 2\pi r h$$ - Surface area of a sphere: $$A_{sphere} = 4\pi r^2$$ - Since the tank has two hemispheres, their combined surface area equals the surface area of one full sphere. 6. **Calculate surface areas:** - Cylinder surface area: $$A_{cyl} = 2\pi \times 22.5 \times 34 = 1530\pi$$ - Sphere surface area: $$A_{sphere} = 4\pi \times (22.5)^2 = 4\pi \times 506.25 = 2025\pi$$ 7. **Total surface area:** $$A_{total} = A_{cyl} + A_{sphere} = 1530\pi + 2025\pi = 3555\pi$$ 8. **Calculate numerical value:** $$A_{total} \approx 3555 \times 3.1416 = 11163.6\text{ cm}^2$$ 9. **Final answer rounded to 1 decimal place:** $$\boxed{11163.6\text{ cm}^2}$$