Subjects geometry

Half Cylinder Edges 5B1586

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1. **Problem Statement:** We have a half-open cylinder with length 455 cm, bottom diameter 91 cm, and top diameter 110 cm. The cylinder is cut into 4 equal pieces along its length. We need to find the radius and diameter of the edges of each piece. 2. **Understanding the problem:** The cylinder is cut along its length into 4 equal parts, so each piece will have length $\frac{455}{4} = 113.75$ cm. 3. **Radius and diameter of bottom and top edges:** - Bottom radius $r_b = \frac{91}{2} = 45.5$ cm - Top radius $r_t = \frac{110}{2} = 55$ cm 4. **Edges of each piece:** Since the cylinder is cut lengthwise, the curved surface is divided into 4 equal arcs. The radius of the edges along the curved surface remains the same as the original radii (bottom and top), but the arc length of each piece is $\frac{1}{4}$ of the total curved length. 5. **Summary:** - Length of each piece = 113.75 cm - Bottom edge radius = 45.5 cm, diameter = 91 cm - Top edge radius = 55 cm, diameter = 110 cm The edges' radius and diameter do not change by cutting lengthwise; only the length of each piece changes. Hence, the edges' radius and diameter remain the same as the original cylinder's bottom and top radii and diameters. Final answer: - Bottom edge radius = 45.5 cm, diameter = 91 cm - Top edge radius = 55 cm, diameter = 110 cm - Length of each piece = 113.75 cm