1. **State the problem:** We need to find the length of the hypotenuse $F$ of a right triangle with legs measuring 34 and 36 units.
2. **Formula used:** According to the Pythagorean theorem, for a right triangle with legs $a$ and $b$ and hypotenuse $c$, the relationship is:
$$c = \sqrt{a^2 + b^2}$$
3. **Apply the formula:** Here, $a = 34$ and $b = 36$, so:
$$F = \sqrt{34^2 + 36^2}$$
4. **Calculate the squares:**
$$34^2 = 1156$$
$$36^2 = 1296$$
5. **Sum the squares:**
$$1156 + 1296 = 2452$$
6. **Find the square root:**
$$F = \sqrt{2452}$$
7. **Simplify the square root:**
$$2452 = 4 \times 613$$
$$F = \sqrt{4 \times 613} = \sqrt{4} \times \sqrt{613} = 2\sqrt{613}$$
8. **Approximate the value:**
$$\sqrt{613} \approx 24.7588$$
$$F \approx 2 \times 24.7588 = 49.5176$$
**Final answer:**
$$F \approx 49.52$$
Hypotenuse Length 22F605
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