1. The problem asks for the measure of each interior angle in a regular hexagon. 2. The formula to find the sum of interior angles of a polygon with $n$ sides is: $$\text{Sum of interior angles} = (n-2) \times 180$$ 3. For a regular polygon, all interior angles are equal, so each interior angle is: $$\text{Each interior angle} = \frac{(n-2) \times 180}{n}$$ 4. For a hexagon, $n=6$, so substitute into the formula: $$\text{Each interior angle} = \frac{(6-2) \times 180}{6} = \frac{4 \times 180}{6}$$ 5. Simplify the fraction: $$\frac{4 \times 180}{6} = \frac{\cancel{4} \times 180}{\cancel{6} \times 1} = \frac{2 \times 180}{3}$$ 6. Calculate the numerator: $$2 \times 180 = 360$$ 7. Divide by 3: $$\frac{360}{3} = 120$$ 8. Therefore, each interior angle of a regular hexagon measures $120^\circ$.