1. **Problem statement:** We need to find the height $y$ of an isosceles triangle where the two equal sides each measure 11.5 m and the angle adjacent to the height is 57°.
2. **Understanding the triangle:** The height $y$ splits the isosceles triangle into two right triangles. Each right triangle has a hypotenuse of 11.5 m and an angle of 57° adjacent to the height.
3. **Formula used:** In a right triangle, the height $y$ opposite the angle 57° can be found using the sine function:
$$y = 11.5 \times \sin(57^\circ)$$
4. **Calculate the sine value:** Using a calculator or sine table,
$$\sin(57^\circ) \approx 0.8387$$
5. **Calculate the height:**
$$y = 11.5 \times 0.8387 = 9.64405$$
6. **Round to 2 decimal places:**
$$y \approx 9.64$$ meters
**Final answer:** The height $y$ of the isosceles triangle is approximately **9.64 m**.
Isosceles Height 5Ccc47
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