1. **State the problem:** We need to find the length of the hypotenuse of an isosceles right triangle where each leg measures 12 cm.
2. **Recall the formula:** In an isosceles right triangle, the legs are equal, and the hypotenuse $h$ is given by the Pythagorean theorem:
$$h = \sqrt{leg^2 + leg^2}$$
3. **Apply the formula:** Substitute the leg length 12 cm:
$$h = \sqrt{12^2 + 12^2}$$
4. **Calculate inside the square root:**
$$h = \sqrt{144 + 144}$$
$$h = \sqrt{288}$$
5. **Simplify the radical:**
Factor 288 as $144 \times 2$:
$$h = \sqrt{144 \times 2}$$
Use the property $\sqrt{a \times b} = \sqrt{a} \times \sqrt{b}$:
$$h = \sqrt{144} \times \sqrt{2}$$
Since $\sqrt{144} = 12$:
$$h = 12\sqrt{2}$$
6. **Final answer:** The length of the hypotenuse is $12\sqrt{2}$ cm.
Isosceles Hypotenuse 8D8614
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