1. **Problem statement:** Given kite ABCD with BN = 15 and AB = 17, find the length of diagonal BD.
2. **Understanding the kite properties:** In kite ABCD, diagonals intersect at right angles. BN is perpendicular to AC at point N.
3. **Given data:**
- BN = 15
- AB = 17
- AN = 4.6
- NC = 6
4. **Goal:** Find BD, which is the length from B to D.
5. **Step 1: Use right triangle ABN to find BN and AN relationship:**
Since AB = 17 and BN = 15, use the Pythagorean theorem in triangle ABN:
$$AB^2 = AN^2 + BN^2$$
6. **Step 2: Calculate AN using Pythagorean theorem:**
$$17^2 = AN^2 + 15^2$$
$$289 = AN^2 + 225$$
$$AN^2 = 289 - 225 = 64$$
$$AN = \sqrt{64} = 8$$
7. **Step 3: Check given AN:** The problem states AN = 4.6, but calculation shows AN = 8. This suggests a discrepancy or that AN = 4.6 is approximate or for another segment. We will proceed with the calculated AN = 8 for accuracy.
8. **Step 4: Find diagonal AC:**
$$AC = AN + NC = 8 + 6 = 14$$
9. **Step 5: Use right triangle BND to find BD:**
Since BN is perpendicular to AC at N, and BD is the diagonal from B to D, BD can be found by:
$$BD = 2 \times BN = 2 \times 15 = 30$$
This is because in a kite, one diagonal is bisected by the other at right angles.
**Final answer:**
$$\boxed{BD = 30}$$
Kite Diagonal A1Df95
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