1. **State the problem:** A knight moves forward 3.6 cm from the center of one square to another, then moves diagonally across to the center of the destination square. We need to find the total distance moved by the knight, rounded to 2 decimal places. 2. **Understand the movement:** The knight first moves forward 3.6 cm (a straight line). Then it moves diagonally across the square. Since the knight moves from the center of one square to the center of the next diagonally, this diagonal distance is the hypotenuse of a right triangle with legs equal to the side length of the square. 3. **Assumption:** The forward move of 3.6 cm corresponds to the side length of the square (since it moves from center to center of adjacent squares). 4. **Calculate the diagonal distance:** Using the Pythagorean theorem, the diagonal distance $d$ is $$d = \sqrt{3.6^2 + 3.6^2}$$ 5. **Simplify:** $$d = \sqrt{2 \times 3.6^2} = \sqrt{2} \times 3.6$$ 6. **Calculate numerical value:** $$d = 1.4142 \times 3.6 = 5.09 \text{ cm (rounded to 2 decimal places)}$$ 7. **Total distance moved:** The knight moves forward 3.6 cm, then diagonally 5.09 cm, so total distance $D$ is $$D = 3.6 + 5.09 = 8.69 \text{ cm}$$ **Final answer:** The knight moved a total of **8.69 cm**.