1. **State the problem:** Calculate the area of an irregular polygon shaped like an "L" with given side lengths: vertical left side 10 in, top horizontal side 9 in, bottom horizontal side 15 in, and right vertical small side 5 in. 2. **Approach:** We can find the area by dividing the "L" shape into two rectangles and summing their areas. 3. **Identify rectangles:** - Rectangle A (top part): width = 9 in, height = 5 in (since the right vertical small side is 5 in) - Rectangle B (bottom part): width = 15 in - 9 in = 6 in (the remaining horizontal length), height = 10 in - 5 in = 5 in (remaining vertical length) 4. **Calculate areas:** - Area of Rectangle A = width \times height = $9 \times 5 = 45$ sq. in. - Area of Rectangle B = width \times height = $6 \times 5 = 30$ sq. in. 5. **Sum areas:** $$\text{Total area} = 45 + 30 = 75 \text{ sq. in.}$$ 6. **Final answer:** The area of the figure is **75 sq. in.**