1. **Problem Statement:** Find the area and perimeter of an L-shaped figure composed of five equal squares arranged with three squares vertically on the left and two squares horizontally extending from the top-right of the column. 2. **Understanding the shape:** The figure consists of 5 equal squares. Let the side length of each square be $s$ units. 3. **Area calculation:** The area of one square is $s^2$. Since there are 5 squares, the total area is: $$\text{Area} = 5 \times s^2 = 5s^2$$ 4. **Perimeter calculation:** To find the perimeter, we trace the outer edges of the L-shape. - The vertical side on the left has 3 squares, so length $3s$. - The bottom side is $s$ (bottom square width). - The horizontal top side has 2 squares, so length $2s$. - The right vertical side has 2 squares, so length $2s$. - The indentation creates an inner corner, so we must count the edges carefully. The perimeter is the sum of the outer edges: $$\text{Perimeter} = 3s + s + 2s + 2s + s + s = 10s$$ (Counting each outer edge segment: left vertical $3s$, bottom horizontal $s$, top horizontal $2s$, right vertical $2s$, plus the two small vertical edges of length $s$ each on the indentation.) 5. **Final answers:** - Area: $5s^2$ square units - Perimeter: $10s$ units Since the side length $s$ is not given, the answers are expressed in terms of $s$.