1. **State the problem:** We need to find the area of an L-shaped polygon composed of two rectangles and a triangular cutout. 2. **Identify the shapes and dimensions:** - Vertical rectangle: height = 30 cm, width = 2 cm - Horizontal rectangle: length = 8 cm, height = 2 cm - Triangular cutout formed by a diagonal line from the right end of the horizontal rectangle down to the vertical rectangle. 3. **Calculate the area of the two rectangles:** - Area of vertical rectangle = height \times width = $30 \times 2 = 60$ cm² - Area of horizontal rectangle = length \times height = $8 \times 2 = 16$ cm² - Total area before subtracting the triangle = $60 + 16 = 76$ cm² 4. **Determine the dimensions of the triangular cutout:** - The triangle is right-angled with base = 8 cm (horizontal length) and height = 2 cm (vertical height of the horizontal rectangle). 5. **Calculate the area of the triangular cutout:** - Area = $\frac{1}{2} \times base \times height = \frac{1}{2} \times 8 \times 2 = 8$ cm² 6. **Calculate the final area of the L-shaped polygon:** - Area = Total rectangle area - Triangle area = $76 - 8 = 68$ cm² **Final answer:** The area of the shape is **68 cm²**.