1. **State the problem:** We need to find the area of an L-shaped lot with given side lengths: top horizontal segment = 30 m, right vertical segment = 9 m, bottom horizontal segment = 11 m, and left vertical segment = 18 m. 2. **Formula and approach:** The L-shaped lot can be divided into two rectangles. The area of the lot is the sum of the areas of these two rectangles. 3. **Identify dimensions of rectangles:** - The left vertical segment is 18 m, and the right vertical segment is 9 m, so the vertical difference is $18 - 9 = 9$ m. - The bottom horizontal segment is 11 m, and the top horizontal segment is 30 m, so the horizontal difference is $30 - 11 = 19$ m. 4. **Calculate areas of the two rectangles:** - Rectangle 1 (top part): width = 30 m, height = 9 m $$\text{Area}_1 = 30 \times 9 = 270\,m^2$$ - Rectangle 2 (bottom part): width = 11 m, height = 9 m (the vertical difference) $$\text{Area}_2 = 11 \times 9 = 99\,m^2$$ 5. **Sum the areas:** $$\text{Total Area} = 270 + 99 = 369\,m^2$$ 6. **Answer:** The area of the L-shaped lot is **369 m²**. Therefore, the correct choice is **b. 369 m²**.