1. **State the problem:** We need to find the area of a piece of land shaped as a combination of a trapezoid and a parallelogram. 2. **Identify the dimensions:** - Top base of trapezoid = 23 m - Bottom base of trapezoid = 10.2 m - Total height = 16.9 m - Height of parallelogram (bottom segment) = 6.1 m - Height of trapezoid (top segment) = 16.9 m - 6.1 m = 10.8 m 3. **Formulas:** - Area of trapezoid = $$\frac{(b_1 + b_2)}{2} \times h$$ where $b_1$ and $b_2$ are the parallel sides and $h$ is the height. - Area of parallelogram = base $\times$ height. 4. **Calculate area of trapezoid:** $$\text{Area}_{trap} = \frac{(23 + 10.2)}{2} \times 10.8$$ $$= \frac{33.2}{2} \times 10.8$$ $$= 16.6 \times 10.8$$ $$= 179.28\, m^2$$ 5. **Calculate area of parallelogram:** Base = 23 m (same as top base) Height = 6.1 m $$\text{Area}_{para} = 23 \times 6.1 = 140.3\, m^2$$ 6. **Total area:** $$\text{Area}_{total} = 179.28 + 140.3 = 319.58\, m^2$$ **Final answer:** The area of the piece of land is $$319.58\, m^2$$.