1. **State the problem:** We need to find how many boxes of lawn seed are required to cover the area formed by a square ABCD and a semicircle with diameter BD. The radius of the semicircle is 4 m, and each box covers 25 m². 2. **Identify the dimensions:** Since BD is the diameter of the semicircle and the radius is 4 m, the diameter BD = 2 \times 4 = 8 m. 3. **Find the area of the square ABCD:** The square has side length BD = 8 m. $$\text{Area of square} = \text{side}^2 = 8^2 = 64 \text{ m}^2$$ 4. **Find the area of the semicircle:** The area of a full circle is $\pi r^2$, so the semicircle area is half of that. $$\text{Area of semicircle} = \frac{1}{2} \pi r^2 = \frac{1}{2} \pi (4)^2 = \frac{1}{2} \pi 16 = 8\pi \text{ m}^2$$ 5. **Calculate the total area to be covered:** $$\text{Total area} = \text{Area of square} + \text{Area of semicircle} = 64 + 8\pi$$ 6. **Approximate the total area:** Using $\pi \approx 3.1416$, $$64 + 8 \times 3.1416 = 64 + 25.1328 = 89.1328 \text{ m}^2$$ 7. **Calculate the number of boxes needed:** Each box covers 25 m², so $$\frac{89.1328}{25} = 3.5653$$ Since we cannot buy a fraction of a box, we round up to the next whole number. **Number of boxes needed = 4** **Final answer:** 4 boxes of lawn seed are needed.