1. **Problem statement:** We need to find the length of segment $AD$ in a triangular pyramid with given angles and side lengths.
2. **Given data:**
- $BC = 37$ cm
- Angle at $D$ adjacent to the dotted line (which is $BD \perp BC$) is $33^\circ$
- Angle at $A$ near $AB$ is $54^\circ$
- Angle at $B$ is $125^\circ$
- $BD$ is perpendicular to $BC$
3. **Step 1: Analyze triangle $BCD$**
Since $BD \perp BC$, triangle $BCD$ is right-angled at $B$.
4. **Step 2: Find length $BD$ using angle $33^\circ$ at $D$**
In right triangle $BCD$, angle $D = 33^\circ$, hypotenuse $CD$ unknown, but we can express $BD$ and $CD$ in terms of $BC$.
5. **Step 3: Use angle sum in triangle $ABC$ to find $AC$**
Angles in triangle $ABC$ are:
- At $A$: $54^\circ$
- At $B$: $125^\circ$
- At $C$: $180^\circ - 54^\circ - 125^\circ = 1^\circ$
6. **Step 4: Use Law of Sines in triangle $ABC$**
$$\frac{AC}{\sin 125^\circ} = \frac{BC}{\sin 54^\circ}$$
$$AC = \frac{37 \times \sin 125^\circ}{\sin 54^\circ}$$
Calculate:
$$\sin 125^\circ \approx 0.8192, \sin 54^\circ \approx 0.8090$$
$$AC \approx \frac{37 \times 0.8192}{0.8090} \approx 37.47 \text{ cm}$$
7. **Step 5: Use Law of Cosines in triangle $ABD$ to find $AD$**
We need to find $AD$. We know angle at $A$ is $54^\circ$, and $BD$ is perpendicular to $BC$, so $BD$ is height from $B$ to $DC$.
8. **Step 6: Calculate $BD$ using right triangle $BCD$**
In right triangle $BCD$, angle at $D$ is $33^\circ$, so:
$$BD = BC \times \sin 33^\circ = 37 \times 0.5446 = 20.15 \text{ cm}$$
9. **Step 7: Calculate $CD$ using right triangle $BCD$**
$$CD = BC \times \cos 33^\circ = 37 \times 0.8387 = 31.02 \text{ cm}$$
10. **Step 8: Use triangle $ABD$ to find $AD$**
We know $AB$ (which equals $AC$ from step 6) is approximately $37.47$ cm, and $BD = 20.15$ cm.
11. **Step 9: Use Pythagoras theorem in triangle $ABD$**
Since $BD$ is perpendicular to $BC$, and $AD$ is the hypotenuse of triangle $ABD$:
$$AD = \sqrt{AB^2 + BD^2} = \sqrt{37.47^2 + 20.15^2}$$
Calculate:
$$AD = \sqrt{1404.1 + 406.0} = \sqrt{1810.1} = 42.54 \text{ cm}$$
**Final answer:**
$$\boxed{42.54 \text{ cm}}$$
Length Ad 1D4007
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