1. **Problem Statement:** Given points W, X, Y, Z and lines formed between pairs (W,X), (W,Y), (W,Z), (X,Y), (X,Z), and (Y,Z), prove the theorem: "If W is a point, there exists at least one line not containing W." 2. **Understanding the Theorem:** The theorem claims that among all lines formed by these points, at least one line does not pass through point W. 3. **Step 1:** Consider the line $p$ that contains points X and Y. By definition, line $p$ passes through X and Y only. 4. **Step 2:** Since $p$ contains X and Y, and W is a different point, line $p$ does not contain W. This is because a line is uniquely determined by two distinct points, and W is not one of them here. 5. **Step 3:** The existence of line $p$ (containing X and Y) proves there is at least one line that does not contain W. 6. **Additional Note:** Lines such as (W,X), (W,Y), and (W,Z) do contain W, but lines like (X,Y), (X,Z), and (Y,Z) do not necessarily contain W. **Final Conclusion:** Therefore, the theorem is true: there exists at least one line (for example, line $p$ through X and Y) that does not contain point W.