1. **Problem Statement:** We need to find the locus of points equidistant from the line segments PR and QR in triangle PQR.
2. **Key Concept:** The locus of points equidistant from two line segments that meet at a point is the bisector of the angle formed by those segments.
3. **Explanation:**
- The line segments PR and QR meet at vertex R.
- Points equidistant from PR and QR lie on the angle bisector of angle PRQ.
4. **Conclusion:** The correct option is B: the bisector of angle PRQ.
Thus, the locus is the angle bisector of angle PRQ.
Locus Equidistant E71142
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