1. **State the problem:** We are given a trapezoid QRTU with midsegment PS.
The lengths are:
- $TU = w$
- $PS = w + 10$
- $QR = -w + 50$
We need to find the value of $w$.
2. **Recall the midsegment formula for trapezoids:**
The midsegment length is the average of the lengths of the two bases:
$$PS = \frac{TU + QR}{2}$$
3. **Substitute the given expressions:**
$$w + 10 = \frac{w + (-w + 50)}{2}$$
4. **Simplify inside the numerator:**
$$w + 10 = \frac{\cancel{w} - \cancel{w} + 50}{2} = \frac{50}{2}$$
5. **Simplify the fraction:**
$$w + 10 = 25$$
6. **Solve for $w$:**
$$w = 25 - 10$$
$$w = 15$$
**Final answer:**
$$\boxed{15}$$
Midsegment Trapezoid 5A25Af
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