1. The problem asks to find the missing angle $h$ in a nonagon (9-sided polygon) where the other 8 angles are given as 164°, 135°, 150°, 113.3°, 160°, 135°, 163°, and 100.2°. 2. The formula for the sum of interior angles of a polygon with $n$ sides is: $$\text{Sum of angles} = (n-2) \times 180^\circ$$ For a nonagon, $n=9$, so: $$\text{Sum of angles} = (9-2) \times 180^\circ = 7 \times 180^\circ = 1260^\circ$$ 3. The sum of the given 8 angles plus the unknown angle $h$ must equal 1260°: $$164 + 135 + 150 + 113.3 + 160 + 135 + 163 + 100.2 + h = 1260$$ 4. Calculate the sum of the known angles: $$164 + 135 + 150 + 113.3 + 160 + 135 + 163 + 100.2 = 1120.5$$ 5. Substitute back and solve for $h$: $$1120.5 + h = 1260$$ 6. Isolate $h$: $$h = 1260 - 1120.5$$ 7. Calculate $h$: $$h = 139.5$$ Therefore, the missing angle $h$ measures **139.5°**.