1. **State the problem:** Find the area of an oval (ellipse) with a vertical height of 15 ft and a horizontal width of 4 ft. 2. **Formula for the area of an ellipse:** $$\text{Area} = \pi \times a \times b$$ where $a$ is the semi-major axis and $b$ is the semi-minor axis. 3. **Identify the axes:** - The total height is 15 ft, so the semi-major axis $a = \frac{15}{2} = 7.5$ ft. - The total width is 4 ft, so the semi-minor axis $b = \frac{4}{2} = 2$ ft. 4. **Calculate the area:** $$\text{Area} = \pi \times 7.5 \times 2 = 15\pi$$ 5. **Final answer:** $$\text{Area} \approx 15 \times 3.1416 = 47.12 \text{ square feet}$$ The area of the oval is approximately 47.12 square feet.