1. **Problem statement:** We need to find the total amount of paint required to paint the top hemispherical part of 3000 Bosu exercise balls. Each ball's top is a hemisphere with an outside diameter of 0.8 meters. 2. **Given data:** - Diameter of hemisphere $d = 0.8$ m - Radius $r = \frac{d}{2} = 0.4$ m - Number of balls $n = 3000$ - Paint coverage per gallon = 35 m² 3. **Formula for surface area of a hemisphere:** $$A = 2\pi r^2$$ This formula gives the curved surface area of a hemisphere. 4. **Calculate surface area of one hemisphere:** $$A = 2 \times \pi \times (0.4)^2 = 2 \times \pi \times 0.16 = 0.32\pi \approx 1.0053 \text{ m}^2$$ 5. **Calculate total surface area for 3000 balls:** $$A_{total} = 3000 \times 1.0053 = 3015.9 \text{ m}^2$$ 6. **Calculate gallons of paint required:** $$\text{Gallons} = \frac{A_{total}}{35} = \frac{3015.9}{35} \approx 86.17$$ 7. **Final answer:** Approximately 86.17 gallons of paint are required to paint the top hemispherical parts of 3000 Bosu balls.