1. **State the problem:** We are given two parallel lines \(a\) and \(b\) cut by a transversal, with angles \( (2x - 5)^\circ \) on line \(a\) and \( (x + 20)^\circ \) on line \(b\). We need to find the value of \(x\).
2. **Identify the relationship:** Since lines \(a\) and \(b\) are parallel, the angles given are corresponding angles and therefore equal.
3. **Set up the equation:**
$$
2x - 5 = x + 20
$$
4. **Solve for \(x\):**
\begin{align*}
2x - 5 &= x + 20 \\
2x - \cancel{x} - 5 &= \cancel{x} + 20 \\
x - 5 &= 20 \\
x - \cancel{5} &= 20 + \cancel{5} \\
x &= 25
\end{align*}
5. **Check the answer:** Substitute \(x=25\) back into the angles:
\begin{align*}
2x - 5 &= 2(25) - 5 = 50 - 5 = 45^\circ \\
x + 20 &= 25 + 20 = 45^\circ
\end{align*}
Both angles are equal, confirming the solution.
**Final answer:** \(x = 25\)
Parallel Angles 6B2968
Step-by-step solutions with LaTeX - clean, fast, and student-friendly.