Subjects geometry

Parallel Angles 6B2968

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1. **State the problem:** We are given two parallel lines \(a\) and \(b\) cut by a transversal, with angles \( (2x - 5)^\circ \) on line \(a\) and \( (x + 20)^\circ \) on line \(b\). We need to find the value of \(x\). 2. **Identify the relationship:** Since lines \(a\) and \(b\) are parallel, the angles given are corresponding angles and therefore equal. 3. **Set up the equation:** $$ 2x - 5 = x + 20 $$ 4. **Solve for \(x\):** \begin{align*} 2x - 5 &= x + 20 \\ 2x - \cancel{x} - 5 &= \cancel{x} + 20 \\ x - 5 &= 20 \\ x - \cancel{5} &= 20 + \cancel{5} \\ x &= 25 \end{align*} 5. **Check the answer:** Substitute \(x=25\) back into the angles: \begin{align*} 2x - 5 &= 2(25) - 5 = 50 - 5 = 45^\circ \\ x + 20 &= 25 + 20 = 45^\circ \end{align*} Both angles are equal, confirming the solution. **Final answer:** \(x = 25\)
(2x - 5)°(x + 20)°ab