1. **Problem Statement:**
Given two parallel lines L1 and L2 intersected by two transversals t1 and t2, find the measures of angles 1, 2, 3, and 4 using the given angles 109° and 87° and the properties of parallel lines and transversals.
2. **Relevant Rules and Formulas:**
- Corresponding angles are equal when two parallel lines are cut by a transversal.
- Alternate interior angles are equal.
- Supplementary angles add up to 180°.
3. **Step-by-step Solution:**
**Angle 1:**
- Angle 1 is at the intersection of L2 and t1, top-right.
- Given angle adjacent to angle 1 is 109°.
- Since angles on a straight line sum to 180°,
$$\angle 1 + 109^\circ = 180^\circ$$
- Subtracting 109° from both sides:
$$\angle 1 = 180^\circ - 109^\circ = 71^\circ$$
**Angle 2:**
- Angle 2 is at the intersection of L1 and t1, bottom-left.
- By the Corresponding Angles Postulate, angle 2 corresponds to angle 1 because L1 and L2 are parallel and t1 is a transversal.
- Therefore,
$$\angle 2 = \angle 1 = 71^\circ$$
**Angle 3:**
- Angle 3 is at the intersection of L2 and t2, left side.
- Given angle adjacent to angle 3 is 87°.
- Angles on a straight line sum to 180°, so
$$\angle 3 + 87^\circ = 180^\circ$$
- Subtracting 87° from both sides:
$$\angle 3 = 180^\circ - 87^\circ = 93^\circ$$
**Angle 4:**
- Angle 4 is at the intersection of L1 and t2, above the lower line.
- By Corresponding Angles Postulate, angle 4 corresponds to angle 3.
- Therefore,
$$\angle 4 = \angle 3 = 93^\circ$$
4. **Final answers:**
- $$\angle 1 = 71^\circ$$
- $$\angle 2 = 71^\circ$$
- $$\angle 3 = 93^\circ$$
- $$\angle 4 = 93^\circ$$
Parallel Lines Angles 0D4Db9
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