1. **State the problem:** Given two parallel lines $m \parallel n$ cut by a transversal $t$, find the value of $x$ when the angles $(5x - 8)^\circ$ and $(4x + 8)^\circ$ are given as shown.
2. **Identify the relationship:** Since $m \parallel n$ and $t$ is a transversal, the angles given are alternate interior angles, which are congruent.
3. **Set up the equation:**
$$5x - 8 = 4x + 8$$
4. **Solve for $x$:**
Subtract $4x$ from both sides:
$$5x - \cancel{4x} - 8 = \cancel{4x} + 8$$
$$x - 8 = 8$$
Add 8 to both sides:
$$x - \cancel{8} + \cancel{8} = 8 + 8$$
$$x = 16$$
5. **Conclusion:** The value of $x$ is $16$.
This means the angles are equal, confirming the property of alternate interior angles when lines are parallel.
Parallel Lines X 4308D8
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