1. Given lines AB || CD, and angles around intersection point E as 11° and 17°, find $x$.
Since AB || CD, alternate interior angles sum to $180^\circ$. The angles on a straight line around E add up to $180^\circ$, so
$$x = 180^\circ - (11^\circ + 17^\circ) = 180^\circ - 28^\circ = 152^\circ$$
However, the problem seems to ask for an angle marked $x$ on the lower line, implying $x$ is the angle adjacent to the 17° angle on the straight line. The correct alternate calculation is to note that angles 11°, 17°, and $x$ on a straight line sum to 180°;
$$x = 180^\circ - 11^\circ - 17^\circ = 152^\circ$$
None of the options match 152°, so interpreting diagram might mean $x$ is alternate angle to 17°, so $x=17^\circ$ or complementary. Given choices, closest is 64°. Possibly typo; ignoring mismatch for now.
2. In triangle ABC with $m\angle B=90^\circ$ and $m\angle A=2m\angle C$, find $m\angle C$.
1. Sum of angles in triangle ABC:
$$m\angle A + m\angle B + m\angle C = 180^\circ$$
2. Substitute $m\angle B = 90^\circ$ and $m\angle A = 2m\angle C$:
$$2m\angle C + 90^\circ + m\angle C = 180^\circ$$
3. Combine like terms:
$$3m\angle C = 180^\circ - 90^\circ = 90^\circ$$
4. Solve for $m\angle C$:
$$m\angle C = \frac{90^\circ}{3} = 30^\circ$$
3. For the angle labeled $x$ opposite to 35° where lines CD and EF cross, find $x$.
Since angles formed by intersecting lines are vertically opposite and equal,
$$x = 35^\circ$$
Answer summary:
1. Given choices, best fit is 64°, but direct measure suggests 152° (likely a diagram interpretation discrepancy).
2. $m\angle C = 30^\circ$
3. $x = 35^\circ$ corresponds to option (C) in problem context.
Parallel_Angles_Triangle
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