1. **Problem statement:** Given parallelogram ABCD with angles at A as $6x$, at B as $72^\circ$, and at D as $72^\circ$, find the value of $x$. 2. **Recall properties of parallelograms:** Opposite angles are equal, and adjacent angles are supplementary (sum to $180^\circ$). 3. Since angle B and angle D are both $72^\circ$, and opposite angles are equal, angle A and angle C must be equal as well. 4. Adjacent angles sum to $180^\circ$, so angle A and angle B satisfy: $$6x + 72 = 180$$ 5. Solve for $x$: $$6x + 72 = 180$$ $$6x = 180 - 72$$ $$6x = 108$$ $$x = \frac{108}{6}$$ $$x = 18$$ 6. **Answer:** The value of $x$ is $18$.