1. **Problem statement:** In parallelogram PQRS, given that diagonal SQ = 26, find the length of segment ST, where T is the intersection of diagonals PR and SQ.
2. **Key property:** In any parallelogram, the diagonals bisect each other. This means that the point of intersection T divides each diagonal into two equal parts.
3. Since T is the midpoint of diagonal SQ, the lengths ST and TQ are equal.
4. Given that the entire diagonal SQ = 26, we can write:
$$SQ = ST + TQ = 2 \times ST$$
5. Solving for ST:
$$ST = \frac{SQ}{2} = \frac{26}{2} = 13$$
6. **Answer:** The length of segment ST is 13 units.
Parallelogram Diagonal C28Abd
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