1. **State the problem:** We need to find the values of $w$, $x$, and $y$ in a parallelogram where the sides are labeled as follows: - Side AB: $x + 16$ - Side AD: $3x$ - Side BC: $16w - 29$ - Side CD: $x + y$ 2. **Recall properties of parallelograms:** Opposite sides of a parallelogram are equal in length. Therefore: $$AB = CD \quad \text{and} \quad AD = BC$$ 3. **Set up equations using the property:** $$x + 16 = x + y$$ $$3x = 16w - 29$$ 4. **Solve the first equation:** $$x + 16 = x + y$$ Subtract $x$ from both sides: $$\cancel{x} + 16 = \cancel{x} + y$$ $$16 = y$$ 5. **Solve the second equation:** $$3x = 16w - 29$$ Rewrite as: $$16w = 3x + 29$$ Divide both sides by 16: $$w = \frac{3x + 29}{16}$$ 6. **Summary:** - $y = 16$ - $w = \frac{3x + 29}{16}$ - $x$ remains a variable unless more information is given. **Final answer:** $$y = 16, \quad w = \frac{3x + 29}{16}, \quad x = x$$