1. **Problem statement:** Given parallelogram KLMN with side KL labeled as $x$, side LM as 16, and other segments marked with equal lengths, find the value of $x$. 2. **Recall properties of parallelograms:** Opposite sides are equal in length, so $KL = MN$ and $LM = KN$. 3. Since $LM = 16$, then $KN = 16$. 4. The diagonal $KN$ is intersected by segment $BJ$ at point $J$, with tick marks indicating equal segments on $KN$ and $BJ$. This suggests $BJ$ bisects $KN$ or segments are equal, but the key property is opposite sides equality. 5. Since $LN$ and $NB$ are marked equal, and $B$ is the bottom-left vertex (likely a typo for $M$), this implies $LN = NB$ and $NB$ is part of $LM$. 6. Using the parallelogram property, $KL = MN$, and since $MN$ is composed of segments equal to $LN$ and $NB$, and $LN = NB$, then $MN = 2 imes LN$. 7. Given $LM = 16$, and $LN = NB$, then $MN = 2 imes LN = 2 imes NB$. 8. Since $KL = MN$, then $x = 2 imes LN$. 9. But $LN$ is half of $LM$ because $LN = NB$ and $LN + NB = LM = 16$, so $LN = 8$. 10. Therefore, $x = 2 imes 8 = 16$. **Final answer:** $$x = 16$$