1. **State the problem:** We need to find the total cost to pave all the grey areas in the picnic area. Each grey shape's area must be calculated, then summed, and finally multiplied by 12 (cost per m²). 2. **Identify the shapes and their dimensions:** Each square is 1 m². - Left trapezoid: base1 = 1 m, base2 = 2 m, height = 2 m - Right triangle next to it: base = 2 m, height = 2 m - Parallelogram above and right: base = 3 m, height = 2 m - Right trapezoid on far right: base1 = 1 m, base2 = 2 m, height = 2 m - Small right trapezoid below right trapezoid: base1 = 2 m, base2 = 3 m, height = 1 m 3. **Formulas:** - Area of trapezoid: $$\text{Area} = \frac{(\text{base}_1 + \text{base}_2)}{2} \times \text{height}$$ - Area of triangle: $$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$$ - Area of parallelogram: $$\text{Area} = \text{base} \times \text{height}$$ 4. **Calculate each area:** - Left trapezoid: $$\frac{(1 + 2)}{2} \times 2 = \frac{3}{2} \times 2 = \cancel{\frac{3}{2}} \times \cancel{2} = 3$$ m² - Right triangle: $$\frac{1}{2} \times 2 \times 2 = \frac{1}{2} \times 4 = 2$$ m² - Parallelogram: $$3 \times 2 = 6$$ m² - Right trapezoid on far right: $$\frac{(1 + 2)}{2} \times 2 = 3$$ m² (same as left trapezoid) - Small right trapezoid below: $$\frac{(2 + 3)}{2} \times 1 = \frac{5}{2} \times 1 = 2.5$$ m² 5. **Sum all areas:** $$3 + 2 + 6 + 3 + 2.5 = 16.5$$ m² 6. **Calculate total cost:** $$16.5 \times 12 = 198$$ **Final answer:** The company will charge 198 to pave all the grey areas.