1. **State the problem:** Find the perimeter and area of a rectangle with vertices at (2,4), (2,6), (8,6), and (8,4) on the coordinate plane. 2. **Formula for perimeter and area of a rectangle:** - Perimeter $P = 2(\text{length} + \text{width})$ - Area $A = \text{length} \times \text{width}$ 3. **Find the length and width:** - Length is the horizontal distance between (2,4) and (8,4): $$\text{length} = 8 - 2 = 6$$ - Width is the vertical distance between (2,4) and (2,6): $$\text{width} = 6 - 4 = 2$$ 4. **Calculate the perimeter:** $$P = 2(6 + 2) = 2 \times 8 = 16$$ 5. **Calculate the area:** $$A = 6 \times 2 = 12$$ 6. **Final answer:** - Perimeter $P = 16$ units - Area $A = 12$ units$^2$