1. **State the problem:** We need to find the perimeter of a figure composed of a rectangle and a semicircle attached on the right side of the rectangle. 2. **Identify given dimensions:** The rectangle has a length of 7 units and a height of 6 units. The semicircle has a diameter equal to the height of the rectangle, which is 6 units. 3. **Recall formulas:** - Perimeter of rectangle (excluding the side attached to the semicircle) is the sum of the three sides not touching the semicircle: two heights and one length. - Circumference of a full circle is $$C = 2\pi r$$, so the semicircle's perimeter (curved part) is half of that: $$\pi r$$. 4. **Calculate radius of semicircle:** $$r = \frac{diameter}{2} = \frac{6}{2} = 3$$ 5. **Calculate the curved part of the semicircle:** $$\pi r = \pi \times 3 = 3\pi$$ 6. **Calculate the perimeter of the figure:** The perimeter includes: - The top side of the rectangle: 7 units - The left side of the rectangle: 6 units - The bottom side of the rectangle: 7 units - The curved semicircle part: $3\pi$ Note: The right side of the rectangle is replaced by the semicircle's diameter, so it is not counted twice. So, $$P = 7 + 6 + 7 + 3\pi = 20 + 3\pi$$ 7. **Approximate the value:** Using $$\pi \approx 3.1416$$, $$P \approx 20 + 3 \times 3.1416 = 20 + 9.4248 = 29.4248$$ 8. **Round to the nearest tenth:** $$P \approx 29.4$$ units **Final answer:** The perimeter of the figure is approximately **29.4** units.