1. **State the problem:** Calculate the circle's circumference, the square's perimeter, and the parallelogram's perimeter given: - Square area = 28 square inches - Circle radius = 3.5 inches - Parallelogram side lengths = $\frac{20}{3}$ inches and $\frac{25}{6}$ inches 2. **Formulas:** - Square perimeter $P = 4s$ where $s$ is the side length - Circle circumference $C = 2\pi r$ where $r$ is the radius - Parallelogram perimeter $P = 2(a + b)$ where $a$ and $b$ are side lengths 3. **Find the square's side length:** Since area $A = s^2$, then $$s = \sqrt{28} = \sqrt{4 \times 7} = 2\sqrt{7}$$ 4. **Calculate the square's perimeter:** $$P = 4s = 4 \times 2\sqrt{7} = 8\sqrt{7}$$ 5. **Calculate the circle's circumference:** $$C = 2\pi r = 2 \pi \times 3.5 = 7\pi$$ 6. **Calculate the parallelogram's perimeter:** Sum of sides: $$a + b = \frac{20}{3} + \frac{25}{6} = \frac{40}{6} + \frac{25}{6} = \frac{65}{6}$$ Perimeter: $$P = 2 \times \frac{65}{6} = \frac{130}{6} = \frac{65}{3}$$ **Final answers:** - Circle's circumference = $7\pi$ inches - Square's perimeter = $8\sqrt{7}$ inches - Parallelogram's perimeter = $\frac{65}{3}$ inches