1. **State the problem:** We need to find the area of a circle with a diameter of 16 feet. 2. **Formula for the area of a circle:** $$A = \pi r^2$$ where $r$ is the radius of the circle. 3. **Important rule:** The radius is half the diameter. So, $$r = \frac{d}{2}$$ 4. **Calculate the radius:** $$r = \frac{16}{2} = 8 \text{ feet}$$ 5. **Calculate the area:** $$A = \pi (8)^2 = 64\pi \text{ ft}^2$$ 6. **Final answer:** The area of the pitcher's circle is $$64\pi \text{ ft}^2 \approx 201.06 \text{ ft}^2$$ This means the chalk circle covers about 201.06 square feet.