1. **Problem statement:**
We have a right triangle ABC right angled at A with AB = 4 and AC = 6. E is the orthogonal projection of A on BC. S is a direct plane similitude mapping B to A and A to C.
2. **Calculate the ratio $k$ and angle $\alpha$ of $S$:**
- The similitude $S$ maps $B \to A$ and $A \to C$.
- The ratio $k = \frac{|AC|}{|AB|} = \frac{6}{4} = 1.5$.
- The angle $\alpha$ is the oriented angle from vector $\overrightarrow{AB}$ to $\overrightarrow{AC}$.
3. **Find $\alpha$:**
- Since $ABC$ is right angled at $A$, $\angle BAC = 90^\circ$.
- The angle $\alpha = 90^\circ = \frac{\pi}{2}$ radians.
4. **Images of lines under $S$:**
- $S$ maps points, so lines map accordingly.
- $S(B) = A$, $S(A) = C$.
- Line $(AE)$ maps to line $(CF)$ where $F = S(C)$.
- Line $(BC)$ maps to line $(AC)$ because $B \to A$ and $C \to F$.
5. **$E$ is the center of $S$:**
- By definition, the center $E$ satisfies $S(E) = E$.
- Since $S$ is a direct similitude mapping $B \to A$ and $A \to C$, and $E$ is the foot of perpendicular from $A$ to $BC$, $E$ is fixed by $S$.
6. **Prove $A, E, F$ collinear:**
- $F = S(C)$.
- Since $S$ is a similitude with center $E$, points $A, E, F$ lie on a line.
7. **Show $(CF) \parallel (AB)$:**
- $S$ preserves angles and ratios.
- Since $S$ rotates by $\alpha = 90^\circ$, $(CF)$ is image of $(AC)$ rotated by $90^\circ$.
- $(AB)$ is perpendicular to $(AC)$, so $(CF)$ is parallel to $(AB)$.
8. **Construct $F$ and calculate $CF$:**
- $F = S(C)$.
- $CF = k \times BC$ because $S$ scales by $k=1.5$.
- Calculate $BC = \sqrt{AB^2 + AC^2} = \sqrt{4^2 + 6^2} = \sqrt{16 + 36} = \sqrt{52} = 2\sqrt{13}$.
- So $CF = 1.5 \times 2\sqrt{13} = 3\sqrt{13}$.
9. **Dilation $h$ maps $A \to B$ with ratio $1/3$:**
- $h(A) = B$.
10. **Calculate $S \circ h (A)$:**
- $h(A) = B$.
- $S(B) = A$.
- So $S \circ h (A) = A$.
11. **$S \circ h$ is a direct similitude:**
- Ratio is $k \times \frac{1}{3} = 1.5 \times \frac{1}{3} = 0.5$.
- Angle is $\alpha = 90^\circ$.
- Center is $E$ (same as $S$).
12. **Complex form of $S \circ h$ in system $(A, u, v)$:**
- $u = \overrightarrow{AB}$, $v = \frac{1}{|\overrightarrow{AC}|} \overrightarrow{AC}$.
- The similitude is $z \mapsto k e^{i\alpha} z + z_0$ with $k=0.5$, $\alpha=\frac{\pi}{2}$, and center $E$.
**Final answers:**
- Ratio $k = 1.5$.
- Angle $\alpha = \frac{\pi}{2}$.
- $E$ is the center of $S$.
- $F = S(C)$ lies on line $AE$.
- $(CF) \parallel (AB)$.
- $CF = 3\sqrt{13}$.
- $S \circ h (A) = A$.
- $S \circ h$ has ratio $0.5$, angle $\frac{\pi}{2}$, center $E$.
Plane Similitude 4295Fe
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